Dear students,

Let's remember together.

*Question*The radii of two circles are 19 cm and 9 cm respectively.

Find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles.*Answer* Radius (r1) of 1st circle = 19 cm

Radius (r2) or 2nd circle = 9 cm

Let the radius of 3rd circle be r.

Circumference of 1st circle = 2πr1 = 2π (19) = 38π

Circumference of 2nd circle = 2πr2 = 2π (9) = 18π

Circumference of 3rd circle = 2πr

**Given that, **Circumference of 3rd circle = Circumference of 1st circle + Circumference of 2nd circle

2πr = 38π + 18π = 56π

2nr =56n "dividing both sides by 2n"

r = 28

Therefore, the radius of the circle which has circumference equal to the sum of the circumference of the given two circles is 28 cm.

Notice: n is not N , it is by 22/7 or 3.14 "the rule of circle cir. =2nr "

**Maths coordinator **