Dear students,
Let's remember together.
QuestionThe radii of two circles are 19 cm and 9 cm respectively.
Find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles.Answer Radius (r1) of 1st circle = 19 cm
Radius (r2) or 2nd circle = 9 cm
Let the radius of 3rd circle be r.
Circumference of 1st circle = 2πr1 = 2π (19) = 38π
Circumference of 2nd circle = 2πr2 = 2π (9) = 18π
Circumference of 3rd circle = 2πr
Given that, Circumference of 3rd circle = Circumference of 1st circle + Circumference of 2nd circle
2πr = 38π + 18π = 56π
2nr =56n "dividing both sides by 2n"
r = 28
Therefore, the radius of the circle which has circumference equal to the sum of the circumference of the given two circles is 28 cm.
Notice: n is not N , it is by 22/7 or 3.14 "the rule of circle cir. =2nr "
Maths coordinator